1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: One / Two Dimensional Motion

  1. Sep 18, 2010 #1
    3. The attempt at a solution[/b

    I tried to use the

    X= Vixt + 1/2axt^2 => 0= 1/2axt^2+ Vixt + X

    To find the time since there isn't a horizontal distance given.

    Then I realized the initial velocity for x and y direction can't be the same , but I don't have the angle.

    Do i have to find the angle first?

    If so, what do I use ?

    Edit: I understand how to solve it now. Initial velocity in y direction is zero so I can solve for the time using the same equation above.

    Here is the question
     

    Attached Files:

    Last edited: Sep 18, 2010
  2. jcsd
  3. Sep 18, 2010 #2
    It is a horizontal projection so the velocity at the beginning only has an x component. And only the height of the tower is given.
    hint: freefall
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook