In the following, "G" stands for "gamma". Clocks O and O' coincide when they mutually read zero. POV is that of K'. Prove: When O' reads T'>0, the coincident K clock reads more than T'. Proof: When O' reads T', O reads T'/G and O' coincides with K clock at x=GvT'. That clock reads xv/(cc) more than O: T'/G + GvT'v/(cc) = GT' > T'.