http://pokit.org/get/8119a4b8a37171c67971c3fb13b33063.jpg [Broken] Consider picture above. I understand how an integrator behaves when the capacitor is full. It(capacitor) acts as infinite resistance ergo open loop so we get positive saturation at the output. What I don't understand how come we are starting at 0? Doesn't capacitor act like a short circuit in the very first moments of its charging? Effectively making this a voltage follower? (at very first moments). I understand what voltage follower does in situation when the Vin is connected to + lead and we have short circuit between output and - lead. Question risen what would happen if I grounded a + lead and connected Vin to - through a resistor like so: http://pokit.org/get/4b7a8c8dca68aacc548f3a3b2d748715.jpg [Broken] Have I just short circuited the whole op-amp? As it isn't there? Getting weird results from simulations.