[PLAIN]http://pokit.org/get/3deef3b185bf6b18007a25ddc18ce7d5.jpg [Broken] So I have another thread running on op-amps, and while waiting for mr. Jiggy to come back online, I want to ask another op-amp question. This precision diode. I understand what is the point, and why it is so useful. Eliminating that pesky voltage drop on diode, when rectifying <0.6 voltages is very nice. But all in all I do not understand how it works. I've searched the internet high and low, very little answers. So here is my current viewing:(and questions) From the picture I see that the input is connected to the non-inverting lead. This makes the output conduct when the sine wave is in the positive part. Because of that feedback, we have a simple voltage follower, correct? But here is the thing. Don't we have that voltage drop, we are trying to eliminate still at the output? How is this negative feedback correcting? Any help would be appreciated, these op-amps are so versatile I cannot believe it!