- #1
likephysics
- 636
- 2
Homework Statement
I am trying to figure out how this ckt works. But no idea, where to even begin.
see attachment tp.png
Homework Equations
The Attempt at a Solution
Q1 is diode connected. The Vbe temperature dependence is amplified to indicate the temperature. -2mV/ deg C
Gain is about 50.
I simplified the ckt to the one in pdf attachment.
The -15v is added to inverting terminal and -13.85v is added to non-inverting terminal.
Assuming Vbe is 0.64v at room temp, -13.85 and -0.64v add up to -14.5v
The difference between invering and non-inverting terminals is 0.5v.
Can't go any further.