Could someone please show that an open ball is open where the definition of "open" is: A set is open if for each x in U there is an open rectangle A such that x in A is contained in U. Where an open rectangle is (a_1,b_1)×…×(a_n,b_n). I also realize that one can use rectangles or balls, but I would like to see the proof using rectangles, as this is the definition used in Spivak's calculus on manifolds. Please avoid any reference to putting an open ball in this open ball, that will only "push back" the proof. If someone could give a detailed proof that would be much appreciated. The rectangle need not be a hypercube.(adsbygoogle = window.adsbygoogle || []).push({});

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# Open balls are open sets

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