How do i open circuit phase R. Line number 4 on the digram being phase R?
Apr 13, 2009 #1 orla22 22 0 How do i open circuit phase R. Line number 4 on the digram being phase R? Attachments CIRC.jpg 50.1 KB · Views: 424
Apr 13, 2009 #2 Astronuc Staff Emeritus Science Advisor 21,668 5,773 I'm not sure what you mean by 'How do i open circuit phase R'. If the impedance (resistor) in line 4 breaks or burns out it is open. I suspect this is a question about an unbalanced Y.
I'm not sure what you mean by 'How do i open circuit phase R'. If the impedance (resistor) in line 4 breaks or burns out it is open. I suspect this is a question about an unbalanced Y.
Apr 13, 2009 #3 orla22 22 0 ok so i should open circuit it by removing the load in line 4 correct and draw a direct line to the source?
ok so i should open circuit it by removing the load in line 4 correct and draw a direct line to the source?
Apr 13, 2009 #4 Astronuc Staff Emeritus Science Advisor 21,668 5,773 An open circuit means the conduction has failed, i.e. it is broken. If one wants to model an open ciruit, one would have to add a switch, which then opens. For example _______________ is closed _________/ _____ is open
An open circuit means the conduction has failed, i.e. it is broken. If one wants to model an open ciruit, one would have to add a switch, which then opens. For example _______________ is closed _________/ _____ is open
