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Homework Help: Optics - Focal length ect.

  1. Apr 17, 2010 #1
    1. The problem statement, all variables and given/known data
    A building will be photographed with a camera.

    The distance is 490 m to the building.
    The building height is 85m and width 40m.
    You can choose between 35mm, 50mm, 135mm and 250mm lenses (focal length of lenses).
    Select the lens that gives the largest image of the building (whole building should be in the movie). The film has a frame on 24mm36mm.

    a) Which lens do you choose?
    b) How large is the image of the building? Reply with rounded integer.
    c) How large is the distance between the lens and film? Suppose that the lens thickness is negligible. Reply with two decimal places.

    2. Relevant equations

    1/a+1/b=1/f
    1/a=1/b
    h/H=c/d(?)

    3. The attempt at a solution

    40/0,036=1111,111.. 490/1111,111=0,411 (focal length 411?) I think I'm lost already here.
    Or,
    1/40+1/0,036=1/f f=0,0359.. (I'm not sure if this means that 35mm is right or if 50mm is better since it 35,9mm)

    I'm not sure how to use h/H right know.

    I would be so happy if someone could help me!

    /Maria
     
  2. jcsd
  3. Apr 17, 2010 #2

    rl.bhat

    User Avatar
    Homework Helper

    Hi Maria H, welcome to PF.
    If a is the object distance and b is the image distance, then
    magnification m = h/H = b/a.
    Lens equation is
    1/a + 1/b = 1/f rewrite it as
    1 + a/b = a/f.
    1 + 1/m = a/f.
    Substitute the values and find f.
     
  4. Apr 18, 2010 #3
    Thank you very much Rl.Bhat!

    Okey, this is what think.

    1/490m+1/0,036m=27,7798.. 1/27,7798..= 0,03599m 35,99mm

    It means that a focal lenght of 35mm is to short. The photografer have to use the lenght of 50mm. Right?

    Now I have. a=490m f=0,050m

    If I use 1 + 1/m = a/f with m=h/H i get a very strange result. just a few mm. I think it should be rather around 35 an 50 mm.

    I think it would help if a kind soul could show me the steps to find the result to these tasks.
    The only think I feel sure about is that a focal lenght of 50mm i correct.

    /Maria
     
  5. Apr 18, 2010 #4

    rl.bhat

    User Avatar
    Homework Helper

    Your calculation of F is not correct. I think you have made mistake in calculating m.
    1 + 1/m = a/F
    1 + 85/36*10^-3 = 490/F.
    Now calculate F
     
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