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Optics - glass bead

  1. Oct 24, 2004 #1
    Let's say we have an objet O in front on a glass bead. The first surface will be a convex surface, hence the centre of curvature is in the back of the surface, which gives [tex]+R_1[/tex]. The object, is a real object in front of the surface, which makes it [tex]+p_1[/tex], however for the second refraction, we take [tex]q_1[/tex] which becomes [tex]-p_2[/tex] + the diameter of the glass bead.Hopefully I have grasped everything right so far, now what I'm not quite so sure about, does surface 2 have its centre of curvature in the back or in the front of the surface. Logically, I'm thinking the center of curvature is inside since the surface 2 is ). Which will give [tex]-R_2[/tex].

    What I want to be sure to understand, if we have a ) refractice surface, the center of curvature is in front of the surface, and with a ( refracting surface, the center of curvature is in the back of the surface. If i picture the center of curvature as the point were you'd stick the compass in order to make a circle, is that correct?

    Thanks in advance
  2. jcsd
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