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Optics - I have no clue where to start

  1. Mar 17, 2009 #1
    1. The problem statement, all variables and given/known data
    See attached.


    2. Relevant equations
    See attached.


    3. The attempt at a solution
    I have no idea where to start. I've been banging my head against this problem for 2 hours now. I just don't see how on earth I can find theta with respect to x when it appears nowhere in the given equation! I think I am missing a key concept here. I don't want someone to just do the problem for me, but I need a starting direction.

    Thanks!
     

    Attached Files:

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  2. jcsd
  3. Mar 18, 2009 #2

    tiny-tim

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    Welcome to PF!

    Hi DanielFaraday! Welcome to PF! :wink:

    I'm afraid it takes a long time to get an attachment approved (and a lot of members don't like opening them anyway).

    Can you just type out the problem for us? :smile:
     
  4. Mar 18, 2009 #3
    Wow. You mean to tell me that every single attachment is reviewed before others can view it? That's downright laughable. I hope whoever has that job is getting paid. :rofl: Sorry, but that just doesn't make any sense. It creates a massive bottleneck that slows the entire forum down. What is the "Report" button for if not for reporting inappropriate attachments?
     
  5. Mar 18, 2009 #4

    mgb_phys

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    It also stops this foum being banned in schools/colleges/workplaces because someone posted porn, or a virus and it stops people leaving because every second post is an ad for viagra.
     
  6. Mar 18, 2009 #5

    tiny-tim

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    No, it only slows you down. :wink:

    As I said, if you'd care to take the time to type out your problem, we'll take the time to help. :smile:
     
  7. Mar 18, 2009 #6

    Redbelly98

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    Now that the attachment has been approved ...

    It looks like a typo. The first equation should be in terms of x and y, not y and z.

    The description of each aperture (single slit, or rectangular aperture) is really telling you about the limits of integration.
     
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