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Homework Help: Optics in Physics

  1. Feb 22, 2012 #1
    1. The problem statement, all variables and given/known data
    A nearsighted patient's far point is 0.717 m from her eyes. She is able to see distant objects in focus when wearing glasses with a refractive power of -1.45 diopters. What is the distance between her eyes and the glasses?

    di = 0.717m
    refractive power = -1.45 diopters

    2. Relevant equations

    1/do + 1/di = 1/f
    refractive = 1/f

    3. The attempt at a solution

    I first tried to put the refractive power into the focal point using the equation my book gave us.
    -1.45 = 1/f
    f = 1/-1.45

    Then I set up the equation as best as I could

    1/do + 1/.717 = 1/-1.45
    -> 1/do = 1/-1.45 - 1/.717
    -> 1/do = -2.084
    -> do = -.4798

    This answer wasn't correct and I dont even know if I'm doing it right...please help!
  2. jcsd
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