- #1
matematikuvol
- 192
- 0
Optics -- magnification of a converging lens
Dioptry of converging lens is $D=3$. What is magnification ##u##?
##\frac{1}{f}=D## - dioptry.
[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{l}[/tex]
[tex]u=\frac{l}{p}[/tex]
[tex]l=up[/tex]
[tex]D=\frac{l+p}{lp}=\frac{p(u+1)}{up^2}[/tex]
Putting ##d=0.25m##, I get
[tex]0.25\cdot 3\cdot u=u+1[/tex]
and ##u=-4##. Where I make a mistake?
Homework Statement
Dioptry of converging lens is $D=3$. What is magnification ##u##?
Homework Equations
The Attempt at a Solution
##\frac{1}{f}=D## - dioptry.
[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{l}[/tex]
[tex]u=\frac{l}{p}[/tex]
[tex]l=up[/tex]
[tex]D=\frac{l+p}{lp}=\frac{p(u+1)}{up^2}[/tex]
Putting ##d=0.25m##, I get
[tex]0.25\cdot 3\cdot u=u+1[/tex]
and ##u=-4##. Where I make a mistake?