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Optics problem

  1. Aug 16, 2009 #1
    Where do you put an object in front of a concave mirror of focal length 10 cm to produce an image that is inverted and 2.5 times greater than the object?

    I have no idea how to solve this.. help..
     
  2. jcsd
  3. Aug 16, 2009 #2

    Doc Al

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    Staff: Mentor

    What are the basic equations describing spherical mirrors and image formation?
     
  4. Aug 16, 2009 #3
    i only know the equation on how to solve for the focal length

    f= (pq)/(p+q)

    where p is the distance of the object from the mirror and q as the distance of the image from the mirror.
     
  5. Aug 16, 2009 #4

    Doc Al

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    Good. And how does image size relate to p and q?
     
  6. Aug 16, 2009 #5
    i come to think of it, the image size does not change no matter what value of p and q is.

    could that mean that there is no way that the image will be 2.5 times greater than the object?
     
  7. Aug 16, 2009 #6

    Doc Al

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    Staff: Mentor

    You'd better check that assumption. As you move the object around, the position and size of the image will change.
     
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