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AlchemistK
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Homework Statement
The accomodation power of a boy whose far point is at infinity can vary from 40D to 44D.
Using this data find the distance of the retina from the lens.
Homework Equations
Power of lens,P = 1/f(in meters)
f = focal length
lens formula, 1/v - 1/u = 1/f
The Attempt at a Solution
when object is at infinity,
f=1/40 = 2.5 cm
by lens formula,
1/v-(-1/[tex]\infty[/tex]) = 1/2.5
=>1/v - 0 = 1/2.5
=>v=2.5 cm
thus, distance = 2.5cm
Have i done this question right? And do i have to confirm the answer by putting the object at the near point or this is enough?