(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

When one mirror of a michelson interforemeter is translated by 0.0114cm, 523 fringes are observed. Calculate the wavelength of the light.

2. Relevant equations

wavelength = 2dm/m

3. The attempt at a solution

wavelength = 2x0.0114 / 523

= 4.39 ^10

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1. The problem statement, all variables and given/known data

An object 2.5cm high is placed 12 cm in front of a thin lens focal length +3cm. How can i work out the image distance, and the magnification, and nature of the image.

2. Relevant equations

1/f = 1/v - 1/u

M = v/u

3. The attempt at a solution

Image distance i have worked out to be 4cm.

Magnification = v/u = 4/12 = 0.33?

I am unsure what a "nature of the image means"

Thanks for any help, is much appreciated

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# Optics Problems

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