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Elihu5991 said:Homework Statement
REFER TO IMAGE
Homework Equations
SEE ABOVE
The Attempt at a Solution
I haven't been able to start this question. I'm wondering how to find the 'average cost per unit'.
Elihu5991 said:Will it be x^3 or cubed x?, since the function is "wrapped" to ^3?
Elihu5991 said:@DrClaude
I don't now how to find an actual value of x when there's only one real number in the equation: 10?
Optimisation using calculus is a mathematical method used to find the maximum or minimum value of a function. It involves using derivatives and critical points to determine the optimal value of a variable.
The purpose of optimisation using calculus is to find the optimal solution for a given problem. This could involve maximizing profits, minimizing costs, or finding the most efficient design for a system.
The steps involved in optimisation using calculus include: 1) defining the problem and identifying the variables, 2) setting up the objective function, 3) taking the derivative of the function, 4) setting the derivative equal to zero to find the critical points, and 5) evaluating the critical points to determine the optimal solution.
The key concepts in optimisation using calculus include critical points, which are points where the derivative of the function is equal to zero, and the first and second derivatives, which are used to determine whether a critical point is a maximum or minimum value.
Optimisation using calculus has many real-world applications, such as in economics to determine the most profitable production levels, in engineering to design the most efficient structures, and in physics to find the optimal trajectory of a projectile. It is also used in data analysis and machine learning to optimize algorithms and predict outcomes.