1. The problem statement, all variables and given/known data Find the dimensions of the right circular cone of maximum volume that can be inscribed in a sphere of radius 15cm. 2. Relevant equations 3. The attempt at a solution let r be radius of circular base of cone let y be height of small right triangle let h be height of cone r^2 + y^2=225 y=sqrt(225-r^2) h=15+y V=(1/3)pir^2(sqrt(225-r^2) + 15) Now to find V'...I get to 9r^4-2670r^2+195750 = 0 0=3(3r^4-890r^2+65250) Need to solve for r. Took about 2323 lines. Final dimensions; r=11.5 roughly h=24.63 maax volume is 3411.05 ?