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## Homework Statement

The cost of fuel per kilometre for a truck travelling [tex]v[/tex] kilometres per hour is given by the equation [tex] C(v) = \frac{v}{100}+\frac{25}{v}[/tex]. Assume the driver is paid $40/h. What speed would give the lowest cost, including fuel and wagesm for a 1000-km trip?

## Homework Equations

[tex]C(v) = \frac{v}{100}+\frac{25}{v}[/tex]

## The Attempt at a Solution

[tex]C(v) = \frac{v^2+2500}{100v}[/tex]

I simplified it into one expression. From here, I differentiate and find the minimum speed. I divide $40/h by the speed to get $/km which I can then use to solve again?

I do not think this is right.