- #1

cj

- 85

- 0

[tex]v_0cos(\frac {\theta}{2}) \text{ m/s}[/tex]

[tex]\text {where }v_0 = \text{the initial velocity when the ball is thrown horizontally, and}[/tex]

[tex] \theta_0 =\text { the initial elevation angle}[/tex]

[tex] \text{At what }\theta_0 \text{ do I need to throw the ball to achieve maximum height and, conversely, range?}[/tex]

I have a feeling this is a "classic" physics problem. I can't, however, think of the velocity versus launch angle conditions leading to maximum height or range.

The only facts I can cough-up is that at maximum height, vertical velocity = 0. Also, maximum range occurs when the baseball experiences maximum flight time along with maximum horizontal velocity.

Using these relationships to solve for optimum initial launch angle is stumping me.