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Orbiting Satellite.

  1. Sep 11, 2005 #1
    I was hoping someone could check my work for me.

    Question:
    A satellite is in circular orbit 600 km above the Earth's surface, where the free-fall acceleration is 8.21 m/s^2. Take the radius of the earth as 6400 km. Determine the speed of the satellite and the time required to complete one orbit around the earth.

    Work:

    Radius from to center of the earth to the satellite is 600000 m + 6400000 m = 7000000 m.

    For uniform circular motion a = v^2/r, so v = sqrt(ar).

    v = sqrt(ar) = sqrt(8.21 m/s^2 * 7000000 m) = 7580.897 m/s

    d = rt, so t = d/r.

    t = d/r = (2pi * 7000000 m)/(7580.897 m/s) = 5801.727 s

    So with the correct number of sig figs velocity would be 7.58e3 m/s and the time required to complete one orbit would be 5.80e3 s.

    Thanks,
    hk
     
  2. jcsd
  3. Sep 11, 2005 #2

    Janus

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    Looks good.
     
  4. Sep 12, 2005 #3
    Thanks Janus.

    hk
     
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