# Order of elements in a group.

1. May 3, 2013

### Artusartos

I just want to check if there is anything wrong with my understanding...

Let's say we have a group of order 42 that contains $Z_6$. Since the group of units of $Z_6$ has order (3-1)(2-1), it means that we have 2 elements of order 6 in G, right? In other words, for any cyclic subgroup of order n, we just calculate the group of units to see how many elements of order n we have. Is that correct? Also, if we let $P=Z_6$, we can have at most 7 cyclic subgroups of order 6, since 7=42/|N(P)| (where N(P) is the normalizer of P), if N(P)=6 (which is the smallest it can be, since it has to contain $Z_6$). I'm just wondering if my understanding is correct.