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Orthogonal transformations

  1. Jun 29, 2007 #1

    daniel_i_l

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    1. The problem statement, all variables and given/known data
    Given two sub-spaces of R^n - W_1 and W_2 where dimW_1 = dimW_2 =/= 0.
    Prove that there exists an orthogonal transformation T:R^n -> R^n so that
    T(W_1) = T(W_2)


    2. Relevant equations



    3. The attempt at a solution
    If dimW_1 = dimW_2 = m then we can say that {v_1,...,v_m} is a basis of W_1 and {u_1,...,u_m} is a basis of W_2. We can make from these bases of R^n:
    {v_1,...,v_m,a_1,...,a_{n-m}} is a basis of R^n and
    {u_1,...,u_m,b_1,...,b_{n-m}} is also.
    From these we can make orthonormal bases of R^n (via GS) so that:
    {v'_1,...,v'_m,a'_1,...,a'_{n-m}} is an orthonormal basis of R^n and
    {u'_1,...,u'_m,b'_1,...,b'_{n-m}} is also.
    Now we make a transformation where:
    T(v'_i) = u'_i
    T(a'_i) = b'_i
    Now, since the transformation of an orthonormal base gives another orthonormal base it's a ON transformation. And since {v'_1,...,v'_m} is a basis of W_1 and{u'_1,...,u'_m} is a basis of W_2 then T(W_1) = W_2
    Is that a complete proof?
    Thanks.
     
  2. jcsd
  3. Jun 29, 2007 #2

    Dick

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    That's pretty much it. Though you may want to point out that you've diligently applied GS in such a way as to ensure that (v'_1..v'_m) and (u'_1...u'_m) are still a basis for W_1 and W_2. I.e. what order to do GS in? You are probably already thinking of the correct order. I'm just saying this because I can't think of anything else to fault and am wondering why you bothered to post this in the first place. It is really easy.
     
    Last edited: Jun 29, 2007
  4. Jun 30, 2007 #3

    daniel_i_l

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    Gold Member

    Thanks for the comments :)
     
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