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Just wondering if anyone has any thoughts on how to approach this question:

A U-tube has vertical arms of radii 'r' and '2r', connected by a horizontal tube of length 'l' whose radius increases linearly from r to 2r. The U-tube contains liquid up to a height 'h' in each arm. The liquid is set oscillating, and at a given instant the liquid in the narrower arm is a distance 'y' above the equilibrium level.

Show that the potential energy of the liquid is given by...

U = (5/8)g(rho)(pi)(r^2)(y^2)

'y' is the change in height.

Thanks!!

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# Homework Help: Oscillating liquid in U-tube

Can you offer guidance or do you also need help?

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