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Homework Help: Oscillating liquid in U-tube

  1. Sep 17, 2008 #1
    Hi,

    Just wondering if anyone has any thoughts on how to approach this question:

    A U-tube has vertical arms of radii 'r' and '2r', connected by a horizontal tube of length 'l' whose radius increases linearly from r to 2r. The U-tube contains liquid up to a height 'h' in each arm. The liquid is set oscillating, and at a given instant the liquid in the narrower arm is a distance 'y' above the equilibrium level.

    Show that the potential energy of the liquid is given by...

    U = (5/8)g(rho)(pi)(r^2)(y^2)

    'y' is the change in height.

    Thanks!!
     
  2. jcsd
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