1. The problem statement, all variables and given/known data A brass tube of mass 22 kg and length 1.3 m is closed at one end. A wire of mass 9.7 g and length 0.39 meters is stretched near the open end of the tube. When the wire is plucked, it oscillates at its fundamental frequency. By resonance, it sets the air column in the tube oscillating at the column's fundamental frequency. What is the frequency of oscillation of the air in the tube ? M(tuba) = 22Kg L = 1.3m m(wire) = 9.7g l = 0.39m 2. Relevant equations f = v/(wavelength in tube) 3. The attempt at a solution I think that the tuba will fit a wavelength 1.5 times the length of the tuba because it is open at one end. So, 1.5*1.3 = 1.95 which is the wavelenth in the tuba. f = 343/1.95 = 175.897Hz This answer is apparently incorrect. Any ideas?