# Oscillation: Musical Tube and String

• Bryon
In summary: This results in a frequency of 343/0.39 = 126.667 Hz. In summary, the frequency of oscillation of the air in the tube is 126.667 Hz.
Bryon

## Homework Statement

A brass tube of mass 22 kg and length 1.3 m is closed at one end. A wire of mass 9.7 g and length 0.39 meters is stretched near the open end of the tube. When the wire is plucked, it oscillates at its fundamental frequency. By resonance, it sets the air column in the tube oscillating at the column's fundamental frequency.

What is the frequency of oscillation of the air in the tube ?

M(tuba) = 22Kg
L = 1.3m
m(wire) = 9.7g
l = 0.39m

## Homework Equations

f = v/(wavelength in tube)

## The Attempt at a Solution

I think that the tuba will fit a wavelength 1.5 times the length of the tuba because it is open at one end. So, 1.5*1.3 = 1.95 which is the wavelenth in the tuba.

f = 343/1.95 = 175.897Hz

This answer is apparently incorrect. Any ideas?

The correct answer is 343/2.7 = 126.667 Hz. The wavelength in the tube is determined by the speed of sound (343 m/s) divided by the frequency of oscillation. Since the frequency of oscillation is the same as the fundamental frequency of the wire, the wavelength in the tube is equal to the length of the wire. Therefore, the frequency of oscillation of the air in the tube can be calculated by dividing the speed of sound (343 m/s) by the length of the wire (0.39 m).

I would approach this problem by first calculating the fundamental frequency of the wire, which is given by the equation f = 1/2L * √(T/m), where L is the length of the wire, T is the tension, and m is the mass per unit length. Plugging in the values given, we get:

f = 1/2(0.39) * √(9.8/0.0097) = 264.75 Hz

Next, we can use the concept of resonance to determine the frequency of oscillation of the air in the tube. Since the wire is plucked at its fundamental frequency, it will set up standing waves in the air column with the same frequency. In order for this to happen, the length of the air column must be equal to a multiple of half the wavelength of the standing wave. In other words, the length of the air column must be equal to half the wavelength of the standing wave in order for resonance to occur.

Thus, we can set up the equation L = λ/2, where L is the length of the air column and λ is the wavelength of the standing wave. Solving for λ, we get:

λ = 2L = 2(1.3) = 2.6 m

Finally, we can use the equation f = v/λ to calculate the frequency of oscillation of the air in the tube, where v is the speed of sound. Plugging in the values, we get:

f = 343/2.6 = 131.92 Hz

Therefore, the frequency of oscillation of the air in the tube is approximately 131.92 Hz. It is important to note that this is only an approximation, as the actual frequency may be slightly different due to factors such as the thickness and material of the tube walls.

## 1. What is oscillation in the context of a musical tube and string?

Oscillation is the back and forth or up and down movement of a tube or string, resulting in the production of sound waves. In the context of a musical tube and string, oscillation is what creates the vibrations that produce musical notes.

## 2. How does an oscillating musical tube or string produce different pitches?

The pitch of a musical note produced by an oscillating tube or string is determined by its frequency of oscillation. A higher frequency results in a higher pitch, while a lower frequency produces a lower pitch. This is because the frequency of oscillation directly affects the wavelength of the sound waves produced.

## 3. What factors affect the oscillation of a musical tube or string?

The oscillation of a musical tube or string can be affected by several factors, including its length, tension, and density. The longer the tube or string, the lower the frequency of oscillation and the lower the pitch produced. Higher tension and lower density also result in a higher frequency of oscillation and higher pitch.

## 4. What is the relationship between amplitude and loudness in an oscillating musical tube or string?

The amplitude of an oscillating musical tube or string refers to the maximum displacement of the tube or string from its resting position. The larger the amplitude, the louder the sound produced. This is because a larger amplitude results in a greater displacement of air molecules, creating a more intense sound wave.

## 5. How does a musical tube or string produce different harmonics?

Harmonics are frequencies that are integer multiples of the fundamental frequency of a sound wave. In an oscillating musical tube or string, different harmonics are produced by changing the length, tension, or density of the tube or string. Each harmonic has a different frequency and contributes to the overall quality and tone of the sound produced.

• Introductory Physics Homework Help
Replies
5
Views
1K
• Introductory Physics Homework Help
Replies
14
Views
1K
• Introductory Physics Homework Help
Replies
7
Views
1K
• Introductory Physics Homework Help
Replies
1
Views
1K
• Introductory Physics Homework Help
Replies
6
Views
2K
• Introductory Physics Homework Help
Replies
2
Views
907
• Introductory Physics Homework Help
Replies
12
Views
3K
• Introductory Physics Homework Help
Replies
7
Views
2K
• Introductory Physics Homework Help
Replies
3
Views
3K
• Introductory Physics Homework Help
Replies
1
Views
1K