Oscillation of cylinder attached to two springs

In summary, the purpose of studying the oscillation of a cylinder attached to two springs is to understand the behavior of systems involving springs and its practical applications. The mass of the cylinder affects its oscillation by changing the natural frequency of the system, with a heavier cylinder oscillating at a slower rate. The equation for calculating the natural frequency is f = 1/2π √(k/m). The stiffness of the springs affects the oscillation by changing the spring constant, resulting in a higher natural frequency for higher spring constants. The amplitude of the cylinder's oscillation can be affected by factors such as initial displacement, damping coefficient, and external forces.
  • #1
Abhishekdas
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0
Oscillation of cylinder attached to two springs...

Homework Statement


A solid uniform cylinder of mass m performs small oscillations due to the action of two springs attached at its topmost point. Spring have spring constant k. Find time period of these oscillations in the absence of sliding...


Homework Equations


R*alpha= accleration of CM.
Time period = 2pi/(w)



The Attempt at a Solution



Let the cylinder be displaced by a small angle θ.
Assuming extension of spring and the arc R*θ to be in the same line (because θ is very small) we can equate them.
So extension of spring in one case and contaraction of spring in the other case = Rθ

Force due to each spring = kRθ so total force is 2kRθ.
Let friction be f be in the direction of spring force.

Now,

2kRθ+f=mR*alpha (pure rolloing so acc of CM = angular acc)...1

Torque equation is

R*(2kRθ - f)= I*alpha

Subtituting I=mR2/2 and simplifying,

we get alpha = 8kθ/3m

So angular frequency w = 8k/3m and hence T = pi*(3m/2k)1/2

but answer in book is pi/2*(3m/k)1/2...

So can anyone please point out the mistake? if any...Thank you...
 
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  • #2


Your solution looks correct to me. However, it is always a good idea to double check your calculations and make sure all the units are consistent. Also, the answer given in the book may be in a simplified form, so it would be helpful to show your steps of simplification to see where the difference may lie.

Another thing to consider is the initial conditions of the system. Is the cylinder released from rest? If so, the initial angular velocity would be zero and this may affect the final answer.

Overall, I believe your approach and solution are correct. Keep up the good work!
 

1. What is the purpose of studying the oscillation of a cylinder attached to two springs?

The study of oscillation of a cylinder attached to two springs is important in understanding the behavior of systems that involve springs, such as mechanical systems and electrical circuits. It also has practical applications in fields such as engineering and physics.

2. How does the mass of the cylinder affect its oscillation?

The mass of the cylinder affects its oscillation by changing the natural frequency of the system. A heavier cylinder will have a lower natural frequency, meaning it will oscillate at a slower rate compared to a lighter cylinder.

3. What is the equation for calculating the natural frequency of a cylinder attached to two springs?

The equation for calculating the natural frequency of a cylinder attached to two springs is f = 1/2π √(k/m), where f is the natural frequency, k is the spring constant, and m is the mass of the cylinder.

4. How does the stiffness of the springs affect the oscillation of the cylinder?

The stiffness of the springs affects the oscillation of the cylinder by changing the spring constant in the equation for natural frequency. A higher spring constant results in a higher natural frequency, meaning the cylinder will oscillate at a faster rate.

5. What factors can affect the amplitude of the cylinder's oscillation?

The amplitude of the cylinder's oscillation can be affected by factors such as the initial displacement of the cylinder, the damping coefficient of the system, and the strength and direction of external forces acting on the cylinder.

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