Astronauts in space cannot weigh themselves by standing on a bathroom scale. Instead, they determine their mass by oscillating on a large spring. Suppose an astronaut attaches one end of a large spring to her belt and the other end to a hook on the wall of the space capsule. A fellow astronaut then pulls her away from the wall and releases her. The spring's length as a function of time is shown in the figure What is her speed when the spring's length is 1.2 ? Given (seen from a length vs. time graph): Spring's constant: 240N/m Max length of string: 1.4m Min length of string: 0.6m Equilibrium position: 1.0m (if taking the middle) Mass of person attached to string: 54.7kg Frequency: 2 oscillations per 6 seconds Associated formulas: w=root (k/m) w=2(pi)f 1/2mv^2 + 1/2kx^2 = 1/2kA^2 = 1/2 m(Vmax)^2 might be more that I am missing. I have tried the question using the conservation of energy and yielded 2.37m/s, which I think is not possible since the entire string is less than that.