Oscillations Quick Question

  • #1
A graph resembling that of cos(x) is presented in which x is the vert. axis and t is the horizontal axis. Assume that the x coordinate of point R is 0.12 , and the t coordinate of point K is 0.0050.

So . . .
R = (0 , 0.12 m)
K = (.005 s ,0)

What is the period T of oscillations?

I know that a*T = .005 s, where T is the period and a is the fraction of a full wavelength covered over this interval. What is a so I can get T?

Thanks for any hints.
 

Answers and Replies

  • #2
Have you tried using kinematics? You might be able to use the formula d = vit+ ½ at² to find "a" if you mean "a" as in 'acceleration'.
 
  • #3
Gokul43201
Staff Emeritus
Science Advisor
Gold Member
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ms. confused said:
Have you tried using kinematics? You might be able to use the formula d = vit+ ½ at² to find "a" if you mean "a" as in 'acceleration'.
That wouldn't be the right way to do it.

Soaring Crane, you haven't sufficiently described the figure.

Is R at the topmost point (like it would be for cosx) ?
And is K the point where the curve first intersects the t-axis ?
Or are they somethings else ?

Code:
R?
*   *
|        *
|           *
|____________ *K?____
|              *
 
  • #4
Thanks, got the answer.
 

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