- #1
roam
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Homework Statement
I'm trying to solve this problem:
http://img824.imageshack.us/img824/3513/prob1r.jpg
The Attempt at a Solution
I rearranged the equation T=2π√m/k to find the spring constant:
[itex]k= \frac{m}{\left( \frac{T}{2 \pi} \right)^2} = \frac{70}{\left( \frac{6}{2 \pi} \right)^2}= 76.7628 \ N/m[/itex]
To find the original unstretched length I solve for y in F=ky and subtract it from 60 m:
F=-ky
[itex]y= \frac{-F}{k} = \frac{-mg}{k} = \frac{-70 \times 9.81}{76.7628} = -8.957 \ m[/itex]
The spring is stretched by 8.94 meters from its equilibrium position so the original length is:
60-8.94=51.0543 m
Is this right? And how do I find the damping constant for the cord? What formula do I have to use? Any help is greatly appreciated.
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