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## Homework Statement

A mass m is suspended on a vertical spring. The mass is released from the equilibrium position of the spring without the mass. Find the position of the mass as a function of time, while neglecting friction.

## Homework Equations

ma=-kx + mg

## The Attempt at a Solution

I set the downward motion as positive, thus explaining my - and + choices in the equation. I posed x=Acos(wt) + Bsin(wt) and integrated the ma=-kx + mg equation twice to get a function of x(t). My main problem is that I don't know what to do with the mg factor. When I integrate I get a gt²/2 factor and that's obviously not oscillatory motion.

If the mass is released from the equilibrium position of the spring without the mass, will the mass simply set a new equilibrium position on the spring without engaging an oscillatory motion? I realize this might be a very simple problem, but I haven't done oscillatory motion in a really long time..