eehelp150 said:Would the difference between 10cos and 5cos add a factor of 2 or 1/2 to the # of divisions?
You are making this difficult for yourself if you are attempting to answer this question without first sketching how the oscilloscope is displaying these two signals.eehelp150 said:Would the difference between 10cos and 5cos add a factor of 2 or 1/2 to the # of divisions?
a. Same frequencyCWatters said:No. The 10 and 5 give you the amplitude. For example at a peak, when cos(...) =1, one waveform has the value 10 and the other 5.
Hints:
a) Both waveforms have a common 104t term. What does that mean?
b) One also has another term pi/3. What does that represent?
B would shift the graph over to the right by pi/3?CWatters said:Correct.
Which of a and b shifts the trace left to right along the time axis relative to the other?
So how many divisions will these two traces differ?CWatters said:Correct.
Although I think V2 would be shifted left relative to V1.
1/3 of the period?gneill said:You have calculated the period of the signals (the time for one cycle). How much of one period does the phase angle represent? What is it in milliseconds?
Can you show how you determined the 1/3 value? Is pi/3 really 1/3 of a full circle?eehelp150 said:1/3 of the period?
0.209 ms?
Pi/3 is 1/6 of the total period, so would it be 0.105ms or 1.05 divisions?gneill said:Can you show how you determined the 1/3 value? Is pi/3 really 1/3 of a full circle?
That looks better!eehelp150 said:Pi/3 is 1/6 of the total period, so would it be 0.105ms or 1.05 divisions?
An oscilloscope is a scientific instrument used to measure and display electronic signals. It works by capturing an electrical signal and converting it into a visual representation on a screen, allowing scientists to analyze and measure various parameters of the signal.
To calculate frequency using an oscilloscope, you need to measure the time interval between two adjacent peaks of the signal on the horizontal axis, and then use the formula frequency = 1/time interval.
Peak-to-peak voltage refers to the difference between the maximum positive and negative voltage levels of a signal, while RMS (root mean square) voltage is a value that represents the average voltage of a signal. Peak-to-peak voltage is often used to measure the amplitude of a signal, while RMS voltage is used to determine the power of a signal.
Yes, an oscilloscope can calculate phase difference between two signals by measuring the time delay between the two signals. The phase difference can be calculated using the formula phase difference = (time delay/period) x 360 degrees.
Yes, most modern oscilloscopes have built-in mathematical functions that allow you to perform various calculations such as addition, subtraction, multiplication, and division on the displayed signals. These functions can help you analyze and interpret complex waveforms.