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Otto's cycle

  1. Feb 22, 2012 #1
    I have made an Ottos Cycle graph and found the area Wnet and W12. I now have to find the efficiency η = Wnet/W12 I have found that to be 0,20 but I have no idea what this tells me about the work or anything.

    I need help.
     
  2. jcsd
  3. Feb 23, 2012 #2
    If [itex]\eta[/itex]=.2 then the system is 20% efficient, that is, if you put some energy into the system, only 20% of that energy is converted into work, and the other 80 percent is lost as heat.
     
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