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Output opamp voltage

  1. May 8, 2017 #1
    1. The problem statement, all variables and given/known data
    In the figure below find V(o) / V(s)

    2. Relevant equations
    In an opamp current doesn't enter through the inverting and non-inverting terminals, furthermore in DC conditions a capacitor acts like an open circuit

    3. The attempt at a solution
    The way I see it, both capacitors will act like open circuits current will have no path to follow....
    therefore V(o) will be equal to 0V. also, no initial conditions are mentioned....
    Is this correct?
    or could this be done by a laplace transform??
    figure is attached
    Thank you
     

    Attached Files:

  2. jcsd
  3. May 8, 2017 #2

    gneill

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    Staff: Mentor

    Assume that ##v_s(t)## is an AC source. The gain will depend upon the frequency.
     
  4. May 8, 2017 #3
    Got it, but how can I tell when it's an AC from a DC source
     
  5. May 8, 2017 #4

    gneill

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    Staff: Mentor

    Usually they will use a slightly different symbol for the source.

    upload_2017-5-8_14-52-28.png

    In this case the presence of capacitors in the feedback path is a strong indication that some sort of signal filter is implemented, implying an AC input signal.
     
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