Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Physics
Classical Physics
Mechanics
Output pressure formula for a pressurized waterjet
Reply to thread
Message
[QUOTE="adbury, post: 5478394, member: 594710"] Hello, We have a pressurized Water-jet stream, where the nozzle d= 0.8 mm. We can measure the fluid output in mm[SUP]3[/SUP]/s, to determine the speed by dividing over the area. For this, F=ρAv[SUP]2[/SUP] However, the variable that would be changing, would be the distance from the nozzle to the target. If we assume that as long as the water-jet stream maintains coherence, A[SUB]1[/SUB]=A[SUB]2[/SUB], therefore cancelling A for P=F/A, would the simplified formula: P=ρv[SUP]2[/SUP] Be correct (if we do not want to be overly particular of effects that might not alter this formula in a significant way)? Thanks, Adbury [/QUOTE]
Insert quotes…
Post reply
Forums
Physics
Classical Physics
Mechanics
Output pressure formula for a pressurized waterjet
Back
Top