- #1

ScruffyNerf

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- TL;DR Summary
- If an outside observer sees something fall into a black hole, how does that not break spherical symmetry?

I know that for the infalling observer the horizon is a fake singularity that can be removed via the Eddington-Finkelstein co-ordinates but wouldn't the classic Swartsheild co-ordinates still apply for the outside observer?

So, while for the infaller it takes a finite time, the outside observer will still forever see them on the outside of the black hole, or more appropriately, on a specific set of points outside the black hole. How does this observed mass forever on the side of the black hole not influence the gravity observed by the external observer and not break spherical symmetry? If the outside observer does observe the gravity at the singularity, how does that happen?

So, while for the infaller it takes a finite time, the outside observer will still forever see them on the outside of the black hole, or more appropriately, on a specific set of points outside the black hole. How does this observed mass forever on the side of the black hole not influence the gravity observed by the external observer and not break spherical symmetry? If the outside observer does observe the gravity at the singularity, how does that happen?