# Overcoming friction

I was dragging my frozen 7.2kg turkey due north through the snow at a constant velocity of 2m/s while exerting a horizontal force of only 5.3N. What was the coefficient of friction between the frozen turkey and the snow?

don't you use the formula " FF=ufn" u=coefficient
then mk=ff/fn ?

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PhanthomJay
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I was dragging my frozen 7.2kg turkey due north through the snow at a constant velocity of 2m/s while exerting a horizontal force of only 5.3N. What was the coefficient of friction between the frozen turkey and the snow?

don't you use the formula " FF=ufn" u=coefficient
then mk=ff/fn ?
Yes, m'am, that you do, but what, pray tell, is the force of friction in this example? (It is not often that I know the gender of posters or responders, so I am assuming from your name that you are of the female variety. If not, my apologies for respectfully referring to you as 'madam' Yes, m'am, that you do, but what, pray tell, is the force of friction in this example? (It is not often that I know the gender of posters or responders, so I am assuming from your name that you are of the female variety. If not, my apologies for respectfully referring to you as 'madam' so

fn= 7.2kg
ff= ?

and yes i am a girl:)

PhanthomJay
OK, Mrs. Drake , Newton's first law of motion tells us that if a frozen turkey is moving at constant velocity, there must be no net unbalanced force acting on that bird. So if you're dragging the darn thing forward with a horizontal force of 5.3 N on a level surface, the friction force must be acting backwards with a friction force of _ ?___ N ? But, wait, there's more: The mass of the turkey is 7.2 kg.....It's normal force is it's weight, not its mass, where its weight is equal to ___ ?____ N.?
(I am assuming this is a homework problem, so I don't want to supply the answers). 