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Oxidation number question

  1. May 18, 2015 #1
    1. The problem statement, all variables and given/known data
    The problem is:

    Find the oxidation number of each element in the compound: Pb(O)2

    I said oxidation number of Pb = x, O = -1 since this is a peroxide, therefore oxidation number of Pb is plus 2. However, the solution manual says O is -2 and thus Pb is 2.

    But elsewhere, for the problem BaO2, they say the oxidation number of O is -1 and Ba is +2.

    I'm confused.

    2. Relevant equations


    3. The attempt at a solution
     
  2. jcsd
  3. May 18, 2015 #2

    Borek

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    Staff: Mentor

    PbO2 is not a peroxide.
     
  4. May 18, 2015 #3

    epenguin

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    Homework Helper
    Gold Member

    Not clear whether it is the manual or you who is saying Pb in PbO2 is +2 but now hopefully not.

    I have a vague recollection that lead dioxide did sometimes get improperly and misleadingly called "lead peroxide",
    probably before chemical nomenclature was formalised and the name still hangs around.
     
  5. May 18, 2015 #4

    James Pelezo

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    Gold Member

    Borek is 100% right, it ain't a peroxide ... Hint: Oxy = -2, Calculate oxidation state of Pb.
     
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