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Biology and Chemistry Homework Help
Oxidation Numbers for H3AsO4 and H2S Equation
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[QUOTE="Specter, post: 5876930"] [h2]Homework Statement [/h2] Identify the element oxidized and the element reduced, in this chemical equation: H[SUB]3[/SUB]AsO[SUB]4[/SUB]+H[SUB]2[/SUB]S ---> H[SUB]3[/SUB]AsO[SUB]3[/SUB]+S+H[SUB]2[/SUB]O[h2]Homework Equations[/h2] none [h2]The Attempt at a Solution[/h2] [/B] So I have learned the rules for oxidation numbers: 1. The oxidation number of an element is always 0 regardless of its subscript. This is true as long as they are not part of compound. 2. The oxidation number of a simple ion is the charge of the ion. 3.The oxidation number of oxygen in compounds is -2. 4. The oxidation number of hydrogen in compounds is +1. 5.Group 1 and group 2 metals always have a +1, and +2 value, respectively, in compounds. 6. All other oxidation numbers are assigned so that the net sum of the oxidation numbers equals the net charge of the molecule or complex ion. So with what I know I can figure out the oxidation numbers for the oxygens and hydrogens in the chemical equation but how do I figure out the numbers for arsenic and sulfur? [/QUOTE]
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Oxidation Numbers for H3AsO4 and H2S Equation
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