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[itex]\mathrm{Fe^{3+}(aq) + SCN^{-} (aq) \rightleftharpoons FeSCN^{2+}(aq)}[/itex]

I add some [itex]\mathrm{NaHSO_{3}(s)}[/itex] to the above reaction !

This makes the above chemical solution sour, consequently in a sour solution [itex]\mathrm{HSO^{-}_{3}}[/itex] will reduce Fe^{3+} to Fe^{2+}, meanwhile [itex]HSO_{3}^{-}[/itex] is itself oxidated to [itex]SO^{2-}_{4}[/itex].

a/ The color of the original resolution changes then adding [itex]\mathrm{NaHSO_{3}(s)}[/itex] to yellow.

b/ By adding [itex]\mathrm{NaHSO_{3}(s)}[/itex] to the orginal solution the equilibrium direction changes, such that it runs from right to left.

c/ I need help writing the reaction between [itex]HSO^{-}_{3}[/itex] and [itex]SO^{-}_{4}[/itex].

d/ Which influence does the adding of [itex]HSO^{-}_{3}[/itex] have on the concentration of [itex]Fe^{3+}[/itex]

I hope that there someone out there who is willing to assist me since this is my last post !

Sincerely

Fred

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# Oxidation related question

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