The p-adic numbers Qp don't have a square root of -1, if p=3 mod 4.(adsbygoogle = window.adsbygoogle || []).push({});

So would differentiable functions from Qp-> Qpsatisfy the

Cauchy-Riemann equations? I don't know why not.

To what extent would analysis in Qphave the familiar complex analysis

theorems??? You couldn't prove that Qpis algebraically complete, I

wonder what would block the complex analysis proof of that, that 1/p(x)

would be a bounded entire function if it had no roots.

Laura

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# P-adic analysis question

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