P=F/A problem

Main Question or Discussion Point

I have a tube 1 1/2 diam. wall thickness .120 We need to crush each end about 1 inch in from the end. We are in need of the requirements of a press that will do the job???
your help is needed thank you
 

Answers and Replies

PhanthomJay
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It makes a difference what the material is and what its strength is. Also, it's length must be sufficiently short to prevent buckling before it crushes, or at least it should be sideways supported against buckling, and also to prevent local buckling of the tube wall. What material you talking? Steel, fiberglass, cardboard??
 
steel 3 feet long it will be supported at the other end by a stop bracket the press will have two dies
 
PhanthomJay
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steel 3 feet long it will be supported at the other end by a stop bracket the press will have two dies
Oh, I misuderstood, i think. I was assuming from your title that you wanted to place an axial force on the pipe. But do you want to instead 'squeeze' the ends to flatten the pipe, kind of close it off? If so, I don't think I can help. But please clarify.
 
yes it is to be squeezed
 
PhanthomJay
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yes it is to be squeezed
Oh, sorry. I don't know for sure. These presses are often used to make electrical splices between 2 wires by using an alumimum or steel tube installed over each end, and compressed (squeezed) with a 2 piece circular or hex shaped die. They require usually a minimum 15 ton hydraulic press, sometimes a 60 or even a 100 ton press for diameters over 2". I'm not sure of the wall thickness, though, in this application. You might want to check the tubing manufacturer's recommendations (Burndy and Anderson-Fargo and Alcoa come to mind).
 
Last edited:
stewartcs
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I have a tube 1 1/2 diam. wall thickness .120 We need to crush each end about 1 inch in from the end. We are in need of the requirements of a press that will do the job???
your help is needed thank you
For your particular pipe, collapse is governed by yield strength collapse.

Yield strength collapse pressure is given by:

[tex]P_{yp} = 2Y_p \cdot \frac{(\frac{D}{t} - 1)}{(\frac{D}{t})^2}[/tex]

where,

[tex] P_{yp} [/tex] is the external pressure required to generate minimum yield stress in the pipe
[tex] Y_p [/tex] is the yield strength of the pipe
D is the diameter of the pipe
t is the wall thickness of the pipe

Hope this helps.

CS
 
Stewartcs formula worked well. I came up with 3,827.2 Pyb

Thank you all for your in put

Dell
 

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