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P-Po=density x g x distance?

  1. Nov 13, 2009 #1
    1. The problem statement, all variables and given/known data

    A mountaineer in the Rockies measures the air pressure to be 10% below that at sea level. At what height above sea level does he make the measurement? At this altitude he finds a small mountain lake of fresh water which is 4.3m deep at its deepest point. What is the pressure at the deepest point of the lake

    2. Relevant equations

    P-Po=density x g x distance?

    3. The attempt at a solution
     
  2. jcsd
  3. Nov 13, 2009 #2

    rl.bhat

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    Homework Helper

    Re: Pressure

    Pressure at sea level = pressure due to 76 cm of mercury column.
    10% less of this pressure is 68.4 cm of mercury column.
    So the pressure at the mountain is ρ*g*h'. ρ is the density of the mercury.
     
  4. Nov 16, 2009 #3
    Re: Pressure

    For the 2nd part P = D*G*H. density of water = 1000kg/m^3. After you get the pressure you simply add the atmospheric pressure. P = Pg + Pa. Make sure your units are correct, throws me off a lot.
     
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