Why is the packing fraction important for transporting watermelons and oranges?

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In summary, the conversation discusses the logic behind question 13 c) ii) and iii) in a physics problem, as well as the concept of packing fraction and its relevance to the problem. The participants also discuss the formula for velocity and its relationship to volume. The conversation highlights the importance of understanding packing fraction in order to solve the problem correctly.
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  • #2
The chocolates push each other out of the funnel.
 
  • #3
BvU said:
The chocolates push each other out of the funnel.
ii) there should be a horizontal speed as well, and why would the chocolate pushed out be at the top and come down , i.e. 2r.

iii) understand this now
 
  • #4
aspodkfpo said:
ii) there should be a horizontal speed as well, and why would the chocolate pushed out be at the top and come down , i.e. 2r.
Each spherical chocolate within the outlet horizontal tube is pushed by the one inmediately upstream and it pushes the one inmediately downstream.
There is no gap among them.
Because of that, any fixed point of the outlet tube "sees" five spheres to go by in one second.
A row of five spheres has a length of five diameters.

##Speed=Distance~travelled~by~one~sphere/time=(2r)(5)/1=10r/s##

"As the level in the top of the funnel is steady the number of chocolates going in the top must be the same as the number coming out the bottom of the funnel. This means that 5 chocolates per sec- ond will come out of the funnels."
 
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  • #6
aspodkfpo said:
For c) iii), why did they add a /f for volume?
I believe that is the packing fraction -- the total of the individual candy volumes divided by the bulk volume they occupy. Note the comment below: "b) some students had difficulty interpreting the meaning of a packing fraction"

One way of reasoning your way to the formula above is to start by asking: How much bulk volume is occupied by five candies?

The answer is: ##5\frac{4 \pi r^3}{3f}##. They would occupy ##5 \frac{4}{3}\pi r^3## but they are inefficiently packed. So they occupy more volume than that.
 
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  • #7
aspodkfpo said:
For c) iii), why did they add a /f for volume?
If you do a dimmensional analysis, you could see that the equation is for velocity rather than volume (Volume occupied by 5 spheres per second / Cross area of funnel).

"The packing fraction (f) is defined to be the ratio of the volume of some objects divided by the total volume of space which they occupy.
When arranged randomly the chocolates have a packing fraction of 0.64."

That is the reason that increases the cost of transporting watermelons respect to transporting oranges: you can pack less units in same truck.
 
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1. What is the purpose of packing balls via a funnel?

The purpose of packing balls via a funnel is to efficiently and evenly fill a container or space with spherical objects, such as marbles or ball bearings. This method allows for a compact and organized arrangement of the balls.

2. How does packing balls via a funnel work?

Packing balls via a funnel involves pouring the balls into the top of the funnel and allowing them to flow through the narrow opening into the container below. The balls will stack on top of each other, creating a tight and organized arrangement.

3. What are the benefits of using a funnel to pack balls?

Using a funnel to pack balls offers several benefits, including faster and more efficient packing, a more uniform distribution of the balls, and the ability to pack a larger quantity of balls in a smaller space.

4. Are there any limitations to packing balls via a funnel?

Yes, there are some limitations to packing balls via a funnel. The size of the funnel opening and the size of the balls being packed can affect the efficiency and success of the packing process. Additionally, the shape and material of the funnel can also impact the packing results.

5. Can packing balls via a funnel be applied to other objects besides balls?

Yes, the concept of packing objects via a funnel can be applied to other spherical objects, such as beads or small toys. However, it may not be as effective for non-spherical objects as they may not stack as neatly and evenly as balls.

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