Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Pade integration

  1. Aug 29, 2007 #1
    can we find for a well-behaved f(x) a Rational (Padé approximation) so

    [tex] \int_{0}^{\infty}dx f(x) - \int_{0}^{\infty}dx Q(x) \approx 0 [/tex] ??

    Where Q(x) is a rational function, the main idea is that the integral for Q(x) can be performed exactly , whereas the initial integral of f(x) not.
  2. jcsd
  3. Aug 29, 2007 #2


    User Avatar
    Staff Emeritus
    Science Advisor

    What do you mean by "well behaved"?
  4. Aug 31, 2007 #3
    smooth and differentiable function, for example sin(x) or exp(x^3) ... so it is many times differentiable.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Pade integration
  1. An integral (Replies: 1)

  2. Integral of (Replies: 3)

  3. On Integration (Replies: 4)

  4. An integral (Replies: 2)