1. The problem statement, all variables and given/known data A and B alternate rolling a pair of dice, stopping either when A rolls the sum 9 or when B rolls the sum 6. Assuming that A rolls first, find the probability that the final roll is made by A. 3. The attempt at a solution A rolls a sum 9 on each roll with prob 1/9 B rolls a sum 6 on each roll with prob 5/36 Given that A wins, he will win on an odd number of turns. (since A starts) Let E be the event that the game finishes on an odd number of turns Then P(E) = (1/9)(1-5/36)(1/9)(1-5/36).... Where do I go from here?