How can I determine the parabola of a projectile?

[CallMeDirac]

I have been puzzling over an equation that could be made to show the parabola of a projectile.
So far I have determined that the lateral and vertical velocities are needed, the lateral velocity should determine the x² function but after that I am stuck.

To specify I refused to look this up as that would be admitting defeat so I figured this was second best.

 

[PeroK]

Summary:: I need help on this

I have been puzzling over an equation that could be made to show the parabola of a projectile.
So far I have determined that the lateral and vertical velocities are needed, the lateral velocity should determine the x² function but after that I am stuck.

To specify I refused to look this up as that would be admitting defeat so I figured this was second best.

You need to post what you've done so far. Try to use Latex if you can:

https://www.physicsforums.com/help/latexhelp/

For example, I guess you have: $$x = ut\cos \theta, \ y = ut\sin \theta -\frac{1}{2}gt^2$$

If you reply to this post you should see what I typed to get those formatted equations.

 

[CallMeDirac]

You need to post what you've done so far. Try to use Latex if you can:

https://www.physicsforums.com/help/latexhelp/

For example, I guess you have: $$x = ut\cos \theta, \ y = ut\sin \theta -\frac{1}{2}gt^2$$

If you reply to this post you should see what I typed to get those formatted equations.

\delta x^2 + \delta y + h

Is all I have but I need to account for gravity and find the rate of deceleration

 

[CallMeDirac]

\delta x^2 + \delta y + h

Is all I have but I need to account for gravity and find the rate of deceleration

That didnt work

 

[PeroK]

That didnt work

You're short of a few dollars! You deleted the dollar signs that delimit the Latex.

 

[CallMeDirac]

You're short of a few dollars! You deleted the dollar signs that delimit the Latex.

$$ \Delta x^2 + \Delta y + h $$
?

 

[CallMeDirac]

$$ \Delta x^2 + \Delta y + h $$
?

yes

 

[PeroK]

$$ \Delta x^2 + \Delta y + h $$
?

That's not an expression I can make any sense of.

 

[CallMeDirac]

You're short of a few dollars! You deleted the dollar signs that delimit the Latex.

So far I have

$$ \Delta x^2 + \Delta y + h $$

$$ \Delta x^2 $$ being the denominator in the slope and $$ \Delta y $$ being the numerator ( rise/ run for slope) and H being the height from which it is fired, but I need to factor in gravity and deceleration

 

[PeroK]

So far I have

$$ \Delta x^2 + \Delta y + h $$

$$ \Delta x^2 $$ being the denominator in the slope and $$ \Delta y $$ being the numerator ( rise/ run for slope) and H being the height from which it is fired, but I need to factor in gravity and deceleration

That makes no sense.

If you are trying to do what I think you are doing, you need to start with this:$$x = ut\cos \theta, \ y = ut\sin \theta -\frac{1}{2}gt^2$$

 

[CallMeDirac]

If you are trying to do what I think you are doing, you need to start with this:$$x = ut\cos \theta, \ y = ut\sin \theta -\frac{1}{2}gt^2$$

Can you explain each part.
Sorry, I am a bit new to physics

 

[PeroK]

So far I have

$$ \Delta x^2 + \Delta y + h $$

$$ \Delta x^2 $$ being the denominator in the slope and $$ \Delta y $$ being the numerator ( rise/ run for slope) and H being the height from which it is fired, but I need to factor in gravity and deceleration

The real Paul Dirac would never have done anything like that!

 

[PeroK]

Can you explain each part.
Sorry, I am a bit new to physics

https://courses.lumenlearning.com/physics/chapter/3-4-projectile-motion/

 

[CallMeDirac]

https://courses.lumenlearning.com/physics/chapter/3-4-projectile-motion/

Be back in a moment

 

[CallMeDirac]

https://courses.lumenlearning.com/physics/chapter/3-4-projectile-motion/

The advisor and helper badges are well deserved.

Thanks for the help