1. Aug 30, 2005 #1

   yourmom98

   

   Given {x | -50 < x < 50}, {y | 0 < y < 20} vertex at (0,20) it is a parabola find the equation in (x-h)^2=4p(y-k)
   
   its pretty easy except how do i find p?

    

   yourmom98, Aug 30, 2005
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3. Aug 31, 2005 #2

   HallsofIvy

   

   Science Advisor

   The information you given isn't enough- I assume you mean a parabola with vertical line of symmetry, vertex at (0, 20), and such that when x=50, y= 0.
   (From {x|-50< x< 50}, {y|0< y< 20}, my first guess was x= 50, y= 20 but then I saw that the vertex was at y= 20 so the parabola must be opening downward.)
   
   Since you only ask about p, I assume you understand that since the vertex is at (0, 20), the equation is (x- 0)²= 4p(y- 20). Now, put x= 50, y= 0 in that and solve for p.

    

   HallsofIvy, Aug 31, 2005

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