1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Parabola Problem

  1. Aug 30, 2005 #1
    Given {x | -50 < x < 50}, {y | 0 < y < 20} vertex at (0,20) it is a parabola find the equation in (x-h)^2=4p(y-k)

    its pretty easy except how do i find p?
  2. jcsd
  3. Aug 31, 2005 #2


    User Avatar
    Staff Emeritus
    Science Advisor

    The information you given isn't enough- I assume you mean a parabola with vertical line of symmetry, vertex at (0, 20), and such that when x=50, y= 0.
    (From {x|-50< x< 50}, {y|0< y< 20}, my first guess was x= 50, y= 20 but then I saw that the vertex was at y= 20 so the parabola must be opening downward.)

    Since you only ask about p, I assume you understand that since the vertex is at (0, 20), the equation is (x- 0)2= 4p(y- 20). Now, put x= 50, y= 0 in that and solve for p.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Parabola Problem
  1. Parabola Problem (Replies: 5)

  2. Parabola problem (Replies: 2)

  3. Motion on a parabola (Replies: 4)