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yo0o0ogii
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Homework Statement
How do you figure out the equation of a parabola by only knowing the vertex and ONE of the x intercepts
Vertex: (0, -1920)
X intercept: (96,0)
Help=)
olgranpappy said:the three constants happens to be zero. Which one?
It's actually ...yo0o0ogii said:well the general form of a parabola that is emphasized in vertex form is
y=a(x+h)^2+k
Now it makes no sense at all. Why would they say "ONE OF THE POINTS (not x intercept)" and then give you the x intercept?yo0o0ogii said:k i made a huge mistake
1. Homework Statement
How do you figure out the equation of a parabola by only knowing the vertex and ONE OF THE POINTS ( not x intercept)
Vertex: (0, 1920)
X intercept: (960,0)
its actaully POSITIVE 1960 and 960 not 96
HallsofIvy said:Now it makes no sense at all. Why would they say "ONE OF THE POINTS (not x intercept)" and then give you the x intercept?
In any case, you are told that the vertex is at (0, 1920) so you know the equation is of the form y= a(x- 0)2+ 1920= ax2+ 1920. You only need to determine the single number, a. You also know that (960, 0) is a point on the parabola: that is, when x= 960, y= 0. Put those values of x and y into y= ax2+ 1920 and solve the equation for a.
A parabola is a U-shaped curve that is formed by plotting points that are equidistant from a fixed point (the focus) and a fixed straight line (the directrix).
The vertex of a parabola can be found by using the formula (-b/2a, c - b^2/4a), where a, b, and c are the coefficients of the parabola's equation in standard form (y = ax^2 + bx + c).
The x-intercept of a parabola is the point where the parabola intersects with the x-axis. It is important because it can help determine the roots (or solutions) of the quadratic equation represented by the parabola.
To find the equation of a parabola with known vertex and x-intercept, you can use the standard form of the equation (y = a(x-h)^2 + k) and plug in the coordinates for the vertex (h, k) and the x-intercept into the equation. Then, solve for the value of a using algebraic manipulation.
Yes, a parabola can have more than one x-intercept. If the parabola opens downward, it will have two x-intercepts, while if it opens upward, it will have no x-intercepts. If the parabola is tangent to the x-axis, it will have one x-intercept.