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Parabolic arch

  1. Jun 12, 2007 #1
    "a parabolic arch has an equation x^2 + 10y - 10 = 0. the arch is on a hill with equation y = 0.1x-1. (measurements are in metres).

    "find the points of intersection"
    for this i substituted y =0.1x - 1 into the equation x^2 + 10y - 10 = 0:
    x^2 + 10(0.1x - 1) - 10 = 0
    x^2 + x - 10 - 10 = 0
    x^2 + x - 20 = 0
    should this -20 be 0 instead? (i dunno)


    and then used the quadratic equation so x = 4 or x = -5.
    (putting those amounts into y =0.1x - 1), i have intersections of (4, -0.6) and (-5, -1.5). are these correct?

    also, i dont understand how to draw this. :yuck:

    any help is appreciated!

    ~Amy
     
  2. jcsd
  3. Jun 12, 2007 #2
    k, nevermind (figured it out) :)

    ~Amy
     
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