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Parachute freefall graph

  1. Sep 13, 2009 #1
    1. The problem statement, all variables and given/known data
    A parachutist freefalls from a height of 4000 meters above the ground. Graph his distance vs. time as he falls stop your graph when his parachute opens 200 meters
    2. Relevant equations

    i tried a couple equations
    rate x time=distance
    (final velocity)= (initial velocity)+ acceleration(time)

    3. The attempt at a solution

    i know that the graph is going a downward curve just don't understand how to plot them and the time is what imm trying to figure but it just keeps coming out different.
     
  2. jcsd
  3. Sep 14, 2009 #2

    tiny-tim

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    Last edited by a moderator: Apr 24, 2017
  4. Sep 16, 2009 #3
    Re: Welcome to PF!

    Hello kelsybayless
    For the first 3800 meter this suggestion could be right.
    mgh=1/2mv^2
    Divide out m, h=3800, g=pi^2 so v can be calculated.
    greetings Janm
     
    Last edited by a moderator: Apr 24, 2017
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