Parachute motion question

  • Thread starter Paymemoney
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  • #1
Paymemoney
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Homework Statement


An 80.0kg skydiver jumps out of balloon at an altitude of 1000m and opens the parachute at an altitude of 200m. a) Assume that the total retarding force on the diver is constant at 50.0N with the parachute closed and constant at 3600N with the parachute open, what is the speed of the diver when he lands on the ground?


Homework Equations


Work Done equation
Kinetic Energy equation
Potential energy equation


The Attempt at a Solution



i have tried to solve this question but my answers does not seem correct and logically not possible. So i need some help on how to start this question.

P.S
 

Answers and Replies

  • #2
inutard
93
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Since force is constant and motion is one dimensional, our best friend in this case is the F*d = W, mgh = PE, and 0.5mv^2 = KE equations. There is "positive" energy from the used potential energy in the fall and there is "negative" energy (force is acting opposite to direction of motion) from 800m of constant 50N force and then 200 m of constant 3600N force thereafter. Sum up the "positive" and "negative" energies and you will be able to solve for velocity with 0.5mv^2 = KE (all of the energy is converted to KE).
 
  • #3
Paymemoney
175
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so is the 3600N and 50N Potential Energy or is it the total force exerted within that distance?
 
  • #4
inutard
93
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Force. The potential energy incolves the 1000 m of height.
 
  • #5
Paymemoney
175
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this is what i have done:

PE = mgh
PE = 80 * 9.8 * 1000
PE = 1784J

Now to find the W done for 800m and 200m

W = 50 * 800
W = 4000J negative because it is opposite to the downward direction

W = 3600 * 200
W = -720000J negative because it is opposite to the downward direction

So if i make Total Force=KE then

-4000 + -720000 + 1784 = 0.5* 80 * v^2

722216 = 40 * v^2

v=134.37m/s
 
  • #6
inutard
93
0
Thats quite a big error you have in calculating for potential energy there. The concept is right. The calculations are wrong.
 
  • #7
Paymemoney
175
0
this is what i have done:

PE = mgh
PE = 80 * 9.8 * 1000
PE = 784000Joules

Now to find the W done for 800m and 200m

W = 50 * 800
W = -40000J negative because it is opposite to the downward direction

W = 3600 * 200
W = -720000J negative because it is opposite to the downward direction

So if i make Total Force=KE then

-40000 + -720000 + 784000 = 0.5* 80 * v^2

24000= 40 * v^2

v=24.5m/s

fixed i get the correct answer :) thanks.
 

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